There are 6 red 4 green 5 blue and 5 yellow marbles in a jar.
There are 9 red and 6 green marbles.
So i could pick that red marble or that red marble.
There s two green marbles in the bag.
Write the probability as a fraction in simplest form a decimal and a percent.
There s one blue marble.
Be careful letting children play with marbles they may swallow.
In a jar of red green and blue marbles all but 6 are red marbles all but 8 are green and all but 4 are blue.
If we are too draw another green marble the same probability 6 15 will be resulted.
There s two red marbles in the bag.
Solution from the condition we can determine how many marbles of each color were there in the jar.
Jun 21 2018 1 3 explanation.
There are a total of 14 green and blue marbles so the probability is 14 25 or 56.
You wish to know t probability that the single chosen green or blue marble.
1 answer jim g.
In the bag there are 6 green marbles and 12 red marbles.
There are 9 red and 6 green marbles in a bag.
There are still 6 green marbles and 9 red ones.
A child reaches in the bag and randomly takes one marble.
So this is all the possible outcomes.
9 blue marbles 8 green marbles 4 red marbles 8 white marbles and 6 yellow marbles.
The measure of probability is number of favourable outcomes total possible outcomes a favourable outcome is a green marble of which there are 6.
These are clearly all yellow.
And then there s one blue marble in the bag.
What is the probability of that child getting a green marble.
There are 9 red and 6 green marbles in a bag if a child reaches the bag randomly and picks 6.
Indeed we have these equations where r is the number of red marbles g is the number.
What is the probability of drawing a green marble from the bag.
What percent of the marbles aren t blue.
So i could pick that green marble or that green marble.
At this moment the bag becomes the same as it is before a green marble is drawn i e.
Remember there is one less marble in the jar and that you assume the marble picked was green.
There are 35 marbles in a bag.
7 red 5 green 6 blue pick 7 6 1 14 marbles and at least 1 is red because 14 green blue 11 at least 1 is blue because 14 red green 12 at least 1 is green because 14 red blue 13 picking 13 marbles could result in green marble absence if all 13 marbl.
As both requirements have to be fulfilled the required probability is the multiplication of both 6 15 6 15.